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many improvements (theorem-proof-structure for constant function; corrected errors)

This commit is contained in:
Martin Thoma 2013-12-21 19:10:35 +01:00
parent 01e343f66c
commit a1274e176f
10 changed files with 163 additions and 123 deletions

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@ -3,7 +3,7 @@ Let $f: D \rightarrow \mdr$ with $D \subseteq \mdr$ be a polynomial function and
be a point. Let $d_{P,f}: \mdr \rightarrow \mdr_0^+$
be the Euklidean distance of a point $P$ to a point $\left (x, f(x) \right )$
on the graph of $f$:
\[d_{P,f} (x) := \sqrt{(x_P - x)^2 + (y_P - f(x))^2}\]
\[d_{P,f} (x) := \sqrt{(x - x_P)^2 + (f(x) - y_P)^2}\]
Now there is finite set $M = \Set{x_1, \dots, x_n} \subseteq D$ of minima for given $f$ and $P$:
\[M = \Set{x \in D | d_{P,f}(x) = \min_{\overline{x} \in D} d_{P,f}(\overline{x})}\]
@ -20,6 +20,11 @@ about stationary points will be tremendously usefull:
Then: $f'(x_0) = 0$.
\end{theorem}
So in fact you can calculate the roots of $(d_{P,f}(x))'$ to get
candidates for minimal distance. These candidates include all points
with minimal distance, but might also contain more. Example~\ref{ex:false-positive}
shows such a situation.
Let $S_n$ be the function that returns the set of solutions for a
polynomial $f$ of degree $n$ and a point $P$: