2
0
Fork 0
mirror of https://github.com/MartinThoma/LaTeX-examples.git synced 2025-04-19 11:38:05 +02:00
This commit is contained in:
Martin Thoma 2013-03-28 12:12:51 +01:00
parent e508c58c7e
commit 98227cbdd2
3 changed files with 27 additions and 25 deletions

View file

@ -0,0 +1,6 @@
Der hier abgebildete Graph gibt abhängigkeiten an, wie ich sie wahrnehme.
Empfehlungen
-------------
Will man Caches verstehen, sollte man die TI-Klausuren rechnen.
Weder die OS-Folien, noch die TI-Folien erklären sie so gut wie die TI-KLausuren.

View file

@ -74,7 +74,7 @@ soft/.style ={rectangle, draw=red, thick, fill=red!20,align=center, rounded corn
\path[->] (programmieren) edge[bend left] node {} (pse);
\path[->] (programmieren) edge node {} (os);
\path[->] (swti) edge node {} (pse);
\path[<->] (ro) edge node[anchor=center,above,sloped] {\tiny{Assembler, Adressierung}} (os);
\path[<->] (ro) edge node[anchor=center,above,sloped] {\tiny{Assembler, Adressierung, Caches}} (os);
\path[<->] (algii) edge [very thick] node {} (icpc);
\path[->] (swti) edge node[anchor=center,above,sloped] {\tiny{Prozessmodelle}} (web);
\path[<->] (pse) edge[red] node {} (tse);

View file

@ -1,6 +1,4 @@
\documentclass{article}
\usepackage[pdftex,active,tightpage]{preview}
\setlength\PreviewBorder{2mm}
\documentclass[border=2pt]{standalone}
\usepackage{tikz}
\usetikzlibrary{matrix,calc}
@ -115,26 +113,24 @@
}
\begin{document}
\begin{preview}
\begin{Karnaugh}
\contingut{0,0,0,0,0,1,0,1,1,1,0,0,0,1,0,1}
\implicant{0}{2}
\implicantdaltbaix[3pt]{3}{10}
\implicantcostats{4}{14}
\end{Karnaugh}
\begin{Karnaugh}
\contingut{0,0,0,0,0,1,0,1,1,1,0,0,0,1,0,1}
\implicant{0}{2}
\implicantdaltbaix[3pt]{3}{10}
\implicantcostats{4}{14}
\end{Karnaugh}
\begin{Karnaugh}
\minterms{4,10,11,13}
\maxterms{1,3,6,7,8,9,12,14}
\indeterminats{0,2,5,15}
\implicant{4}{5}
\implicant{11}{10}
\implicant{13}{15}
\implicantcostats{0}{2}
\implicant[3pt]{0}{4}
\implicant[3pt]{5}{13}
\implicant[3pt]{15}{11}
\implicantdaltbaix[3pt]{2}{10}
\end{Karnaugh}
\end{preview}
\begin{Karnaugh}
\minterms{4,10,11,13}
\maxterms{1,3,6,7,8,9,12,14}
\indeterminats{0,2,5,15}
\implicant{4}{5}
\implicant{11}{10}
\implicant{13}{15}
\implicantcostats{0}{2}
\implicant[3pt]{0}{4}
\implicant[3pt]{5}{13}
\implicant[3pt]{15}{11}
\implicantdaltbaix[3pt]{2}{10}
\end{Karnaugh}
\end{document}