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Get center af values without calc

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Ivan Tham 2019-01-13 02:23:14 +08:00 • committed by GitHub
parent 2062dc279b
commit 6f60d2a260
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1 changed files with 4 additions and 4 deletions
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8
tikz/singly-linked-list/singly-linked-list.tex
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@ -3,7 +3,7 @@
\setlength\PreviewBorder{2mm}
\usepackage{tikz}
\usetikzlibrary{calc,shapes.multipart,chains,arrows}
\usetikzlibrary{shapes.multipart,chains,arrows}
\tikzset{
squarecross/.style={
@ -36,9 +36,9 @@
\node[list,on chain] (B) {99};
\node[list,on chain] (C) {37};
\node[squarecross] (D) [right=of C] {};
\draw[*->] let \p1 = (A.two), \p2 = (A.center) in (\x1,\y2) -- (B);
\draw[*->] let \p1 = (B.two), \p2 = (B.center) in (\x1,\y2) -- (C);
\draw[*->] let \p1 = (C.two), \p2 = (C.center) in (\x1,\y2) -- (D);
\draw[*->] (A.two |- A.center) -- (B);
\draw[*->] (B.two |- B.center) -- (C);
\draw[*->] (C.two |- C.center) -- (D);
\end{tikzpicture}
\end{preview}
\end{document}