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Klausur 6, Aufgabe 2 gelöst

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Martin Thoma 2013-09-21 19:57:23 +02:00
parent dffdc90747
commit 69e79a440d
3 changed files with 13 additions and 27 deletions

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@ -1,22 +1,13 @@
"""from math import exp, log
from math import exp, log
def iterate(x):
#return x - (2.0*x - exp(-x))/(2.0+exp(-x)) #Newton
#return 0.5*exp(-x) #F_1
return (-1)*log(2.0*x) #F_2
def iterate(x, times=1):
#x = x - (2.0*x - exp(-x))/(2.0+exp(-x)) #Newton
x = 0.5*exp(-x) #F_1
#x = (-1)*log(2.0*x) #F_2
x = 0.9
for i in range(10):
print (i, x)
x = iterate(x)
"""
from math import log
f = lambda x: -log(2*x)
if times > 0:
x = iterate(x, times-1)
return x
x = 0.35173371124919582602
#x = 0.3517337112491958260249093009299510651715
for i in range(200):
print("x 0.35173371124919582602")
print("x 0.3517337112491958260249093009299510651715")
print("%i %.30f" % (i, x))
x = f(x)
print(iterate(0.5,6))