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Lösung zu Aufgabe 4 Klausur 3 hinzugefügt.
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NeevoLima 2013-09-19 16:32:11 +02:00
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documents/Numerik/Klausur3/Aufgabe4.tex
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\section*{Aufgabe 4} \section*{Aufgabe 4}
TODO
\begin{align*}
I = \int_0^1 \frac{1}{1+4x} dx = \int_0^{0.5} \frac{1}{1+4x} dx +\int_{0.5}^{1} \frac{1}{1+4x} dx = \\ (0.5 - 0) * \frac{f(0) + f(0.5)}{2} + (1 - 0.5) * \frac{f(1) + f(0.5)}{2} = \frac{7}{15}
\end{align*}

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documents/Numerik/Klausur3/Klausur3.pdf
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