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added K3A4
Lösung zu Aufgabe 4 Klausur 3 hinzugefügt.
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\section*{Aufgabe 4}
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TODO
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\begin{align*}
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I = \int_0^1 \frac{1}{1+4x} dx = \int_0^{0.5} \frac{1}{1+4x} dx +\int_{0.5}^{1} \frac{1}{1+4x} dx = \\ (0.5 - 0) * \frac{f(0) + f(0.5)}{2} + (1 - 0.5) * \frac{f(1) + f(0.5)}{2} = \frac{7}{15}
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\end{align*}
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