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Bisection method and Muellers method added

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Martin Thoma 2013-12-30 00:02:54 +01:00
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@ -2,5 +2,8 @@ One solution is
\[x = \frac{(1-i \sqrt{3}) \alpha}{\sqrt[3]{12} \cdot t}
-\frac{(1+i\sqrt{3}) t}{2\sqrt[3]{18}}\]
The verification of this case is pretty much the same as for
The complex conjugate root theorem states
that if $x$ is a complex root of a polynomial $P$, then its
complex conjugate $\overline{x}$ is also a root of $P$.
The solution presented in this case is the complex conjugate of
case 2.2.