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TikZ'en von Bildern
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15 changed files with 163 additions and 16 deletions
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@ -56,3 +56,4 @@ in dem Erstellen dieses Skripts steckt:
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|30.01.2014 | 15:45 - 17:00 | Digitalisieren der Vorlesung von 30.01.2014
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|30.01.2014 | 19:30 - 21:30 | Textsetzung
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|01.02.2014 | 15:40 - 15:50 | Beweis "Möbiustransformation ist Gruppenoperation" hinzugefügt
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|02.02.2014 | 17:00 - 18:00 | TikZ'en von Bildern
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@ -879,7 +879,7 @@ $\partial X$ ist eine Mannigfaltigkeit der Dimension $n-1$.
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\begin{figure}[h!]
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\centering
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\input{figures/topology-oriented-triangle.tex}
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\caption{TODO}
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\caption{Simplizialkomplex mit Totalordnung}
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\end{figure}
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$a < b < c$
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@ -269,7 +269,7 @@ Für einen Weg $\gamma$ sei $[\gamma]$ seine \textbf{Homotopieklasse}\xindex{Hom
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\begin{figure}[htp]
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\centering
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\input{figures/todo.tex}
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\input{figures/topology-paths.tex}
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\caption{Situation aus \cref{kor:gruppenisomorphismus-wege}}.
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\label{fig:situation-gruppenisomorphismus-wege}
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\end{figure}
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@ -826,12 +826,11 @@ $p|V_j: V_j \rightarrow U$ Homöomorphismus.
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%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
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% Mitschrieb vom 19.12.2013 %
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%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
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\begin{bemerkung}%Vorlesung: Folgerung 12.12
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\todo{Hier stimmt was mit den Tilden nicht}
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Sind $p:X \rightarrow X$ und $y: \tilde{Y} \rightarrow X$
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\begin{folgerung}%Vorlesung: Folgerung 12.12
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Sind $p:\tilde{X} \rightarrow X$ und $q: \tilde{Y} \rightarrow X$
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universelle Überlagerungen, so sind $\tilde{X}$ und $\tilde{Y}$
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homöomorph.
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\end{bemerkung}
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\end{folgerung}
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\begin{beweis}
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Seien $x_0 \in X, \tilde{x_0} \in \tilde{X}$ mit
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@ -848,8 +847,8 @@ $p|V_j: V_j \rightarrow U$ Homöomorphismus.
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$p:\tilde{X} \rightarrow X$ mit $(g \circ f) (\tilde{x_0}) = \tilde{x_0}$.
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Da auch $\id_{\tilde{x}}$ diese Eigenschaft hat, folgt mit
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\cref{kor:12.4}: $g \circ f = \id_{\tilde{X}}$.
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Analog $f \circ g = \id_{\tilde{Y}}$. $\qed$
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\cref{kor:12.4}: $g \circ f = \id_{\tilde{X}}$.\\
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Analog gilt $f \circ g = \id_{\tilde{Y}}$. $\qed$
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\end{beweis}
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Die Frage, wann es eine universelle Überlagerung gibt, beantwortet
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@ -600,8 +600,7 @@ Sei im Folgenden \enquote{IWS} die \enquote{Innenwinkelsumme}.
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\end{beweis}
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\section{Weitere Eigenschaften einer euklidischen Ebene}
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\subsection{Strahlensatz}
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\begin{satz}
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\begin{satz}[Strahlensatz]
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In ähnlichen Dreiecken sind Verhältnisse entsprechender Seiten gleich.
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\end{satz}
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@ -612,9 +611,8 @@ Sei im Folgenden \enquote{IWS} die \enquote{Innenwinkelsumme}.
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\label{fig:bild-2}
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\end{figure}
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\begin{beweis}
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TODO
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\end{beweis}
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Der Beweis wird hier nicht geführt. Für Beweisvorschläge wäre ich
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dankbar.
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\begin{figure}[htp]
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\centering
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@ -632,11 +630,11 @@ Sei im Folgenden \enquote{IWS} die \enquote{Innenwinkelsumme}.
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\begin{figure}[ht]
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\centering
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\subfloat[TODO]{
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\subfloat[Zwei kongruente Dreiecke]{
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\input{figures/rectangle-2.1.tex}
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\label{fig:bild-4}
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}%
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\subfloat[TODO]{
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\subfloat[Zwei weitere kongruente Dreiecke]{
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\input{figures/rectangle-2.2.tex}
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\label{fig:bild-5}
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}%
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@ -648,7 +646,7 @@ Der Flächeninhalt eines Dreiecks ist $\nicefrac{1}{2} \cdot \text{Grundseite} \
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\begin{figure}[htp]
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\centering
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\input{figures/todo.tex}
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\input{figures/triangle-4.tex}
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\caption{Flächenberechnung im Dreiecks}
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\label{fig:flaechenberechnung-dreieck}
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\end{figure}
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8
documents/GeoTopo/figures/topology-paths.tex
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8
documents/GeoTopo/figures/topology-paths.tex
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@ -0,0 +1,8 @@
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\begin{tikzpicture}
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\tikzstyle{point}=[circle,thick,draw=black,fill=black,inner sep=0pt,minimum width=4pt,minimum height=4pt]
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\node (a)[point,label=180:$a$] at (0,0) {};
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\node (b)[point,label=0:$b$] at (3, 0) {};
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\draw [rounded corners,->, thick, red] (a) .. controls (0.5,2) .. (2,1) .. controls (2,0.5) .. (a);
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\draw [rounded corners,->, thick, blue] (a) .. controls (1,-1) .. (2,-0.5) .. controls (2.2,-1) .. (b);
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\node at (1,1.2) [red] {$\gamma$};
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\end{tikzpicture}
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25
documents/GeoTopo/figures/triangle-4.tex
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25
documents/GeoTopo/figures/triangle-4.tex
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@ -0,0 +1,25 @@
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\begin{tikzpicture}
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\tkzSetUpPoint[shape=circle,size=10,color=black,fill=black]
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\tkzSetUpLine[line width=1]
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\tkzDefPoints{0/0/A, 4/0/B, -2/3/C}
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\tkzDefLine[orthogonal=through A,/tikz/overlay](B,C) \tkzGetPoint{helper}
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\tkzInterLL(B,C)(A,helper) \tkzGetPoint{La}
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\tkzMarkAngle[arc=l,size=0.4cm,color=red,fill=red!20](A,La,B)
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\tkzLabelAngle[pos=0.25](A,La,B){$\cdot$}
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\tkzDrawPolygon(A,B,C)
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\node at ($(A)+(-0.47,-0.2)$){$A$};
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\node at ($(B)+(0.35,-0.2)$) {$B$}; % \tkzLabelPoint[below](B){$B$} is not accurate enough
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\node at ($(C)+(0.05,0.3)$) {$C$};
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\node[green] at ($(La)+(-0.4,-0.1)$) {$L_A$};
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\tkzDrawSegments[red](A,La)
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\tkzDrawSegments[blue](B,C)
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\tkzLabelSegment[right,red](A,La){$h_a$}
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\tkzLabelSegment[above,blue](B,C){$c$}
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\tkzDrawPoints(A,B,C)
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\tkzDrawPoints[color=green,fill=green](La)
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\end{tikzpicture}
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31
tikz/topology-paths/Makefile
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31
tikz/topology-paths/Makefile
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@ -0,0 +1,31 @@
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SOURCE = topology-paths
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DELAY = 80
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DENSITY = 300
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WIDTH = 512
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make:
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pdflatex $(SOURCE).tex -output-format=pdf
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make clean
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clean:
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rm -rf $(TARGET) *.class *.html *.log *.aux *.data *.gnuplot
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gif:
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pdfcrop $(SOURCE).pdf
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convert -verbose -delay $(DELAY) -loop 0 -density $(DENSITY) $(SOURCE)-crop.pdf $(SOURCE).gif
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make clean
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png:
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make
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make svg
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inkscape $(SOURCE).svg -w $(WIDTH) --export-png=$(SOURCE).png
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transparentGif:
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convert $(SOURCE).pdf -transparent white result.gif
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make clean
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svg:
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#inkscape $(SOURCE).pdf --export-plain-svg=$(SOURCE).svg
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pdf2svg $(SOURCE).pdf $(SOURCE).svg
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# Necessary, as pdf2svg does not always create valid svgs:
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inkscape $(SOURCE).svg --export-plain-svg=$(SOURCE).svg
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3
tikz/topology-paths/Readme.md
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3
tikz/topology-paths/Readme.md
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@ -0,0 +1,3 @@
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Compiled example
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----------------
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BIN
tikz/topology-paths/topology-paths.png
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tikz/topology-paths/topology-paths.png
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15
tikz/topology-paths/topology-paths.tex
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15
tikz/topology-paths/topology-paths.tex
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@ -0,0 +1,15 @@
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\documentclass[varwidth=true, border=2pt]{standalone}
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\usepackage{pgfplots}
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\usepackage{tikz}
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\begin{document}
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\begin{tikzpicture}
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\tikzstyle{point}=[circle,thick,draw=black,fill=black,inner sep=0pt,minimum width=4pt,minimum height=4pt]
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\node (a)[point,label=180:$a$] at (0,0) {};
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\node (b)[point,label=0:$b$] at (3, 0) {};
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\draw [rounded corners,->, thick, red] (a) .. controls (0.5,2) .. (2,1) .. controls (2,0.5) .. (a);
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\draw [rounded corners,->, thick, blue] (a) .. controls (1,-1) .. (2,-0.5) .. controls (2.2,-1) .. (b);
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\node at (1,1.2) [red] {$\gamma$};
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\end{tikzpicture}
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\end{document}
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31
tikz/triangle-4/Makefile
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31
tikz/triangle-4/Makefile
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@ -0,0 +1,31 @@
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SOURCE = triangle-4
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DELAY = 80
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DENSITY = 300
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WIDTH = 512
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make:
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pdflatex $(SOURCE).tex -output-format=pdf
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make clean
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clean:
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rm -rf $(TARGET) *.class *.html *.log *.aux *.data *.gnuplot
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gif:
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pdfcrop $(SOURCE).pdf
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convert -verbose -delay $(DELAY) -loop 0 -density $(DENSITY) $(SOURCE)-crop.pdf $(SOURCE).gif
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make clean
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png:
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make
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make svg
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inkscape $(SOURCE).svg -w $(WIDTH) --export-png=$(SOURCE).png
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transparentGif:
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convert $(SOURCE).pdf -transparent white result.gif
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make clean
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svg:
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#inkscape $(SOURCE).pdf --export-plain-svg=$(SOURCE).svg
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pdf2svg $(SOURCE).pdf $(SOURCE).svg
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# Necessary, as pdf2svg does not always create valid svgs:
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inkscape $(SOURCE).svg --export-plain-svg=$(SOURCE).svg
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3
tikz/triangle-4/Readme.md
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3
tikz/triangle-4/Readme.md
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@ -0,0 +1,3 @@
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Compiled example
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----------------
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BIN
tikz/triangle-4/triangle-4.png
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BIN
tikz/triangle-4/triangle-4.png
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After Width: | Height: | Size: 12 KiB |
33
tikz/triangle-4/triangle-4.tex
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33
tikz/triangle-4/triangle-4.tex
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\documentclass[varwidth=true, border=2pt]{standalone}
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\usepackage{tkz-euclide}
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\usepackage{tikz}
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\usetikzlibrary{patterns}
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\begin{document}
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\usetkzobj{all}
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\begin{tikzpicture}
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\tkzSetUpPoint[shape=circle,size=10,color=black,fill=black]
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\tkzSetUpLine[line width=1]
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\tkzDefPoints{0/0/A, 4/0/B, -2/3/C}
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\tkzDefLine[orthogonal=through A,/tikz/overlay](B,C) \tkzGetPoint{helper}
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\tkzInterLL(B,C)(A,helper) \tkzGetPoint{La}
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\tkzMarkAngle[arc=l,size=0.4cm,color=red,fill=red!20](A,La,B)
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\tkzLabelAngle[pos=0.25](A,La,B){$\cdot$}
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\tkzDrawPolygon(A,B,C)
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\node at ($(A)+(-0.47,-0.2)$){$A$};
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\node at ($(B)+(0.35,-0.2)$) {$B$}; % \tkzLabelPoint[below](B){$B$} is not accurate enough
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\node at ($(C)+(0.05,0.3)$) {$C$};
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\node[green] at ($(La)+(-0.4,-0.1)$) {$L_A$};
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\tkzDrawSegments[red](A,La)
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\tkzDrawSegments[blue](B,C)
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\tkzLabelSegment[right,red](A,La){$h_a$}
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\tkzLabelSegment[above,blue](B,C){$c$}
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\tkzDrawPoints(A,B,C)
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\tkzDrawPoints[color=green,fill=green](La)
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\end{tikzpicture}
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\end{document}
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