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Reduce unnecessary usage of Array.prototype.concat()

There are obviously cases where using `concat` makes perfect sense, since that method doesn't change any of the existing Arrays; see https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/concat

However, in a few cases throughout the code-base that's not an issue and using `concat` only leads to unnecessary intermediate allocations. With modern JavaScript we can thus replace those with a combination of `push` and spread-syntax, which wasn't originally possible when the code was written.
This commit is contained in:
Jonas Jenwald 2022-06-19 12:26:48 +02:00
parent f516bb2174
commit c21f4faaf8
4 changed files with 21 additions and 23 deletions

View file

@ -1663,13 +1663,13 @@ class SimpleSegmentVisitor {
this.symbols = symbols = {};
}
let inputSymbols = [];
for (let i = 0, ii = referredSegments.length; i < ii; i++) {
const referredSymbols = symbols[referredSegments[i]];
const inputSymbols = [];
for (const referredSegment of referredSegments) {
const referredSymbols = symbols[referredSegment];
// referredSymbols is undefined when we have a reference to a Tables
// segment instead of a SymbolDictionary.
if (referredSymbols) {
inputSymbols = inputSymbols.concat(referredSymbols);
inputSymbols.push(...referredSymbols);
}
}
@ -1696,13 +1696,13 @@ class SimpleSegmentVisitor {
// Combines exported symbols from all referred segments
const symbols = this.symbols;
let inputSymbols = [];
for (let i = 0, ii = referredSegments.length; i < ii; i++) {
const referredSymbols = symbols[referredSegments[i]];
const inputSymbols = [];
for (const referredSegment of referredSegments) {
const referredSymbols = symbols[referredSegment];
// referredSymbols is undefined when we have a reference to a Tables
// segment instead of a SymbolDictionary.
if (referredSymbols) {
inputSymbols = inputSymbols.concat(referredSymbols);
inputSymbols.push(...referredSymbols);
}
}
const symbolCodeLength = log2(inputSymbols.length);