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Fetch all indirect objects (i.e. Refs) in NameTree_getAll and NameTree_get (issue 6204)

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This commit is contained in:
Jonas Jenwald 2015-07-14 10:56:56 +02:00
parent 367794f0c7
commit 28f40b1b58
1 changed files with 5 additions and 5 deletions
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10
src/core/obj.js
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@ -1408,7 +1408,7 @@ var NameTree = (function NameTreeClosure() {
var names = obj.get('Names');
if (names) {
for (i = 0, n = names.length; i < n; i += 2) {
dict[names[i]] = xref.fetchIfRef(names[i + 1]);
dict[xref.fetchIfRef(names[i])] = xref.fetchIfRef(names[i + 1]);
}
}
}
@ -1447,9 +1447,9 @@ var NameTree = (function NameTreeClosure() {
var kid = xref.fetchIfRef(kids[m]);
var limits = kid.get('Limits');
if (destinationId < limits[0]) {
if (destinationId < xref.fetchIfRef(limits[0])) {
r = m - 1;
} else if (destinationId > limits[1]) {
} else if (destinationId > xref.fetchIfRef(limits[1])) {
l = m + 1;
} else {
kidsOrNames = xref.fetchIfRef(kids[m]);
@ -1473,9 +1473,9 @@ var NameTree = (function NameTreeClosure() {
// Check only even indices (0, 2, 4, ...) because the
// odd indices contain the actual D array.
m = (l + r) & ~1;
if (destinationId < names[m]) {
if (destinationId < xref.fetchIfRef(names[m])) {
r = m - 2;
} else if (destinationId > names[m]) {
} else if (destinationId > xref.fetchIfRef(names[m])) {
l = m + 2;
} else {
return xref.fetchIfRef(names[m + 1]);